a player hits a 0.05-kg golf ball. if a 3.25 kg m/s impulse is imparted on the ball, what is its final speed? Step 1: Write the given Mass of golf ball is 0.05 kg Impulse of 3.25 kg-m/s Initial velocity of the golf ball (before it is hit) is 0 meter per sec Step 2: Determine the formula/s that will be utilized Impulse is the change in an objects momentum Impulse= mass* (change in velocity) Step 3: Find the final velocity of the ball 3.25 kg-m/s=(0.05 kg)( final velocity- 0 m/s) The final velocity of the golf ball is equal to 65 meter per sec. Therefore, the final velocity of the golf ball (with momentum of 3.25 kg-m/s) is equal to 65 meter per sec. For other practice problems or references, please refer to the following links: brainly.ph/question/1313739 brainly.ph/question/102329 brainly.ph/question/1244270
A gas consist small particles Gases consist of particles (molecules or atoms) that are in constant random motion. ... Gas particles are small and the total volume occupied by gas molecules is negligible relative to the total volume of their container. There are no interactive forces (i.e., attraction or repulsion) between the particles of a gas.
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